3. A, D, C, B
4. A, D, B, C
NET-JUNE-2026
4. Which of the following statements is incorrect ?
1. Given a context free grammar G and a string x, an algorithm can be designed to decide whether x ∈ L(G) in polynomial time.
2. Given a context free grammar L , its complement is also context free.
3. The language {an bm cp: m, n, p ≥ 0, m ≠ n or m ≠ p} is not deterministic context free.
4. Class of deterministic context free languanges is closed under intersection.
NET-JUNE-2026
5. The minimum state of DFA of the following would be the
following:
NET-JUNE-2026
6. - to - 10. Link Questions:
Consider the following Context Free Grammar (G):-
S -> A B
B -> + A B | ∈
A -> C D
D -> * C D | ∈
C -> [S] | x
Variable = {S, A, B, C, D}
Terminals = {+, *, [, ], x }
6. Find the Follow (A) & Follow (C).
1. Follow (A) = { ], $ };
Follow (C) = { +, ], $ };
2. Follow (A) = { +, ], $ };
Follow (C) = { *, +, ], $ };
3. Follow (A) = { *, $, [ };
Follow (C) = { *, [, $ };
4. Follow (A) = { *, ], $ };
Follow (C) = { +, ], $ };
7. In the LL(1) Parsing table of the given CFG, how many valid non blank entities will be there in the rows for variables 'B' and 'D' ?
1. B = 3 entries ; D = 4 entries
2. B = 6 entries ; D = 5 entries
3. B = 2 entries ; D = 3 entries
4. B = 1 entries ; D = 2 entries
8. Identify the correct statement from the following.
1. The given CFG (G) is Left recursive
2. The given CFG (G) needs Left factorization
3. [ [ x * x ] + x] is a valid sentence of this grammar
4. The given CFG (G) has an SLR (0) Parser as well.
9. What will be the FIRST (S) & FIRST (D) ?
1. FIRST (S) = { +, [, x };
FIRST (D) = { +, * };
2. FIRST (S) = { [, ], x };
FIRST (D) = { +, ∈ };
3. FIRST (S) = { [, x };
FIRST (D) = { *, ∈ };
4. FIRST (S) = { [, x, ∈ };
FIRST (D) = { *, ∈ };
10. The I0 state of the canonical LR (0) set of the SLR (1) parser of this CFG has how many productions ?
1. 3
2. 4
3. 5
4. 6
NET-DEC-2025
1. A phase of a compiler which produce the symbol table is
1. Syntax analysis
2. Semantic analysis
3. Target code generation
4. Code optimization
NET-DEC-2025
2. Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: L={ an bn cn : n ≥ 0 } is accepted by a linear bounded automata.
Reason R: Linear bounded automata's recognize exactly the class of context sensitive languages.
In the light of the above statements, choose the most appropriate answer from the options given below
1. Both A and R are correct and R is the correct explanation of A.
2. Both A and R are correct bur R is not the correct explanation of A.
3. A is correct but R is not correct.
4. A is not correct but R is correct.
NET-DEC-2025
3. Match the LIST-I with LIST-II
LIST-I Grammar |
LIST-II All productions are of the form |
A. |
Regular Grammar |
I. |
A -> aX, where a ∈ T and X ∈ V* |
B. |
Unrestricted Grammar |
II. |
A -> xB, A -> x or A -> Bx, A ->x where A, B ∈ V and x ∈ T* |
C. |
Chomsky Normal Form |
III. |
x -> y, where x ∈(V U T)* and y ∈(V U T)* |
D. |
Greibach Normal Form |
IV. |
A -> BC or A -> a , where A, B, C are in V and a is in T |
Choose the correct answer from the options given below:
1. A - II, B - III, C - I, D - IV
2. A - I, B - III, C - II, D - IV
3. A - II, B - III, C - IV, D - I
4. A - II, B - IV, C - I, D - III
NET-DEC-2025
4. Which of the following languages cannot be accepted by push down automata ?
A. L = { an bn cn : n ≥ 0 }
B. L={ ap : p is Prime }
C. L={ wcwR : w ∈ (a, b)* }
D. L={ w ∈ (a, b)* : na(w) = nb(w) }
E. L = { an bm cn+m : n ≥ 0, m ≥ 0 }
Choose the correct answer from the options given below:
1. A, C & D only
2. B, D & E only
3. A & B only
4. C & D only
NET-DEC-2025
5. Let P and Q be two regular expressions over ∑. If p does not contain ∈, then the following equation in R namely,
R = Q + RP
has a unique solution given by,
1. R = Q* P*
2. R = Q P*
3. R = PQ*
4. R = Q* + P* R
NET-DEC-2025
6. What is the space complexity of the CYK algorithm for the P table, where n is the number of words in the sentence and m is the number of non terminal symbols in the grammar ?
1. O(n3)
2. O(nm2)
3. O(n2m)
4. O(n2m2)
NET-DEC-2025
7. If r1 and r2 are regular expressions, then which of the following are correct.
A. L ( r1+ r2 ) = L ( r1 ) U L ( r2 )
B. L ( r1 . r2 ) = L ( r1 ) L ( r2 )
C. L ( ( r1 ) ) = L ( r1 )
D. L ( r1* ) = ( L ( r1 ) )*
Choose the correct answer from the options given below:
1. A & B only
2. B, C & D only
3. A, C, & D only
4. A, B, C & D
NET-DEC-2025
8. Arrange the following in the order of execution while proving a Language is non-Regular using pumping lemma.
A. Split in to xyz satisfying pumping lemma conditions.
B. Assume the language is regular.
C. Choose a string of length ≥ pumping length.
D. Show contradiction when pumping y.
Choose the correct answer from the options given below:
1. B, C, D, A
2. C, D, A, B
3. B, C, A, D
4. A, B, C, D
NET-DEC-2025
9. Match the LIST-I with LIST-II
LIST-I Input |
LIST-II Compiler Phase |
A. |
Syntax Tree |
I. |
Code Generator |
B. |
Character Stream |
II. |
Syntax Analyzer |
C. |
Intermediate Represen- tation |
III. |
Semantic Analyzer |
D. |
Token Stream |
IV. |
Laxical Analyzer |
Choose the correct answer from the options given below:
1. A - II, B - III, C - IV, D - I
2. A - III, B - IV, C - I, D - II
3. A - III, B - I, C - IV, D - II
4. A - I, B - IV, C - II, D - III
NET-DEC-2025
10. Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: If L is Regular, then its complement L' is necessarily regular.
Reason R: Complement of a language can be obtained by swapping final and non-final states in a DFA.
In the light of the above statements, choose the most appropriate answer from the options given below
1. Both A and R are correct and R is the correct explanation of A.
2. Both A and R are correct bur R is not the correct explanation of A.
3. A is correct but R is not correct.
4. A is not correct but R is correct.
NET-DEC-2025
11. Arrange the following tasks of Laxical Analyzer in correct sequence:
A. Token Generation.
B. Removal of comments / White sphere.
C. Buffering and reading source characters.
D. Return token stream to parser.
Choose the correct answer from the options given below:
1. A, B, C, D
2. B, A, C, D
3. C, B, A, D
4. B, A, D, C
NET-JUNE-2025
1. Arrange the following parsers in increasing order of their power of handling grammars i.e. from the least powerfull parser to the most powerfull parser.
A. LR(0) B. LR(1) C. LALR(1) D. LL(0) E. SLR
Choose the correct answer from the options given below:
1. LL(0) -> LR(0) -> SLR -> LR(1) -> LALR(1)
2. SLR -> LR(0) -> LL(0) -> LR(1) -> LALR(1)
3. LL(0) -> LR(0) -> SLR -> LALR(1) -> LR(1)
4. LR(0) -> LL(0) -> SLR -> LR(1) -> LALR(1)
NET-JUNE-2025
2. Consider the following DFA that generates set of strings over = ∑{a, b, c}
Now identify that which of the followings is the best description of the language for the above DFA
1. L = ( a* + b* + c* )*
2. L = ( a + b + c )* (abc)* ( a + b + c )*
3. L = {Set of strings, all starting with 'a, b, c' but ending with 'c'}
4. L = {Set of strings, all having even count (including 0) of substring 'abc'}
NET-JUNE-2025
3. Match the LIST-I with LIST-II
LIST-I |
LIST-II |
A. |
Type 3 Grammar |
I. |
V -> ( V U ∑ )* |
B. |
Type 2 Grammar |
II. |
λVβ -> λ(V U ∑)* β , Where (λ, β)∈ (V U ∑)* |
C. |
Type 1 Grammar |
III. |
( V U ∑ )* ->
( V U ∑ )* |
D. |
Type 0 Grammar |
IV. |
V -> V∑ | ∑ |
Choose the correct answer from the options given below:
1. A -> II, B -> III, C -> IV, D -> I
2. A -> III, B -> I, C -> IV, D - II
3. A -> IV, B -> I, C -> II, D -> III
4. A -> III, B -> II, C -> I, D -> IV
NET-JUNE-2025
4. Consider the following DFA
Which of the following NFA is valid for the given DFA ?
NET-JUNE-2025
6. - to - 10. Link Questions:
Consider the following Three Address code sample for solving the questions:
100: t1 = y+2
101: initial = x / t1
102: limit = 10
103: if i>j goto 105
104: goto 111
105: if num > b goto 107
106: goto 111
107: num = limit - 1
108: b = y+2
109: i = i - num
110: goto 103
111: i = i - num
112: k = j+b
6. Which of the followings is the correct Flow graph for the TAC given in the passage ?
1.
0 1 0 0 0 0 0
0 0 1 1 0 0 0
0 0 0 0 0 0 1
0 0 0 0 1 1 0
0 0 0 0 0 0 1
0 1 0 0 0 0 0
0 0 0 0 0 0 0
|
2.
0 1 0 0 0 0
0 0 1 0 0 0
1 0 1 0 0 0
0 1 0 0 0 1
0 0 0 0 0 1
0 0 0 0 0 1
|
3.
0 1 0 0 0 0 0
0 0 0 1 0 1 0
0 0 0 0 0 0 1
0 0 1 0 0 1 0
0 0 0 0 0 0 1
0 1 0 0 0 0 0
0 1 0 0 0 0 0
|